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In a parallel circuit, ET = 120 V, R = 30 Ω, and XL = 60 Ω. What is the phase angle (angle theta)?

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Phase angle (∅) in a parallel RL circuit is given by the formula; tan∅
= (I_(L) )/(I_(L))

where
I_(L) is current through the inductor and given by
I_(L) = (voltage)/(X_(L))

and
I_(R) is current through the resistor and given by
I_(R) = (voltage)/(R)

hence, tan∅
= 30/60 or ∅ = 26.565 degree

User Treckstar
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