Question

In a parallel circuit, ET = 120 V, R = 1500 Ω, and XL = 1000 Ω. What is the apparent power?

Answer 1

Apparent power is 17.31Volt-amperes.

Explanation:

In a parallel circuit, we are given with
`E_(T)=120V`,R=1500Ω and
`X_(L)`=1000Ω.

And we are asked to find apparent power.

Apparent power is the combination of true power and reactive power.

In other words we can say that in a power triangle, apparent power is the hypotenuse where as true power and reactive power are sides.

Let us find true power first.

True power =
`(E_(T)^(2))/(R) =(120^(2))/(1500)=9.6watts`

The Reactive power=
`(E_(T)^(2))/(X_(L))=(120^(2))/(1000) =14.4VARs`

Now Apparent power=
`\sqrt{9.6^(2)+14.4^(2)}=17.31VA`