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Subject to some of (3/5 + 1/5i) and (4/5 - 2/5i) from (9/5 - 1/5i). the result is what

Subject to some of (3/5 + 1/5i) and (4/5 - 2/5i) from (9/5 - 1/5i). the result is-example-1

2 Answers

4 votes

Answer:

Result = 2/5

Step-by-step explanation:

Question: Subtract to sum of (3/5 + 1/5i) and (4/5 - 2/5i) from (9/5 - 1/5i).

First we will take sum of (3/5 + 1/5i) and (4/5 - 2/5i):

(3/5 + 1/5i) + (4/5 - 2/5i)

= 3/5 + 1/5i + 4/5 - 2/5i

= 3/5 + 4/5) + (1/5i - 2/5i)

= (7/5 - 1/5i)

Now subtract (7/5 - 1/5i) from (9/5 - 1/5i).

(9/5 - 1/5i) - (7/5 - 1/5i)

= 9/5 - 1/5i - 7/5 -1/5i

= (9/5 - 7/5) - (1/5i + 1/5i)

= (2/5) - 0

= 2/5

Result = 2/5

User Anuj Khandelwal
by
8.6k points
3 votes

The correct answer is: 2/5.

Step-by-step explanation:

First you have to add the following expressions:


((3)/(5)+(1)/(5)i)+((4)/(5)-(2)/(5)i) \\ ((3)/(5)+ (4)/(5))+((1)/(5)i-(2)/(5)i) \\= (7)/(5)-(1)/(5)i

Now subtract the above expression from
((9)/(5)-(1)/(5)i):


((9)/(5)- (1)/(5)i) - ((7)/(5) -(1)/(5)i) \\ ((9)/(5) -(7)/(5)) + ((1)/(5)i -(1)/(5)i) \\ (2)/(5) \\


Hence the correct answer is 2/5.


User Stovfl
by
8.2k points

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