Final answer:
The polynomial function f(x)=x³+x²+10x+10 has one real zero and two nonreal zeros.
Step-by-step explanation:
The polynomial function f(x)=x³+x²+10x+10 has two real zeros and one nonreal zero.
To determine the number of real zeros, we can use the discriminant. The discriminant is calculated as b² - 4ac. In this case, the coefficients are a = 1, b = 1, and c = 10. The discriminant is 1² - 4(1)(10) = -39. Since the discriminant is negative, the quadratic formula will yield two complex solutions.
Since the function intersects the x-axis at exactly one location, we can conclude that there is one real zero and two nonreal zeros.