Question

How many moles of Pb(SO4)2 are equivalent to 186.7 g of Pb(SO4)2

Answer 1

Answer : The number of moles of
`Pb(SO_4)_2` is 0.6156 moles.

Solution : Given,

Mass of
`Pb(SO_4)_2` = 186.7 g

Molar mass of
`Pb(SO_4)_2` = 303.256 g/mole

Formula used :

`\text{ Moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}`

Now we have to calculate the moles of
`Pb(SO_4)_2`.

`\text{ Moles of }Pb(SO_4)_2=\frac{\text{ Given mass of }Pb(SO_4)_2}{\text{ Molar mass of }Pb(SO_4)_2}`

`\text{ Moles }{Pb(SO_4)_2}=(186.7g)/(303.256g/mole)=0.6156moles`

Therefore, the number of moles of
`Pb(SO_4)_2` is 0.6156 moles.