Question

An archer shot a 0.06 kg arrow at a target the arrow accelerated at 5,000 m/s squared to reach a speed of 50.0 m/s as it is left the bow.During this acceleration what was the net force to the nearest newton?

Answer 1

300 N

Step-by-step explanation:

Answer 2

the net force to the nearest newton is 300 N

Step-by-step explanation:

The computation of the net force to the nearest newton is shown below:

According to the newton second law of motion, the force is proportional directly to the change rate in momentum

So,

Resulted force = mass × acceleration

F = 0.06 kg × 5,000 m/s

= 300 N

Hence, the net force to the nearest newton is 300 N