Question

Vertex Form: y - 2 = -2 (x-4)^2
Standard Form?
Intercept Form?

Answer 1

Vertex form :
`y=-2(x-4)^2+2`

Intercept Form:
`y=-2(x-5)(x-3)`

Explanation:

We are given

`y-2=-2(x-4)^2`

Simplifying we get

Adding 2 on both sides

`y=-2(x-4)^2+2`

This is the vertex form

Now

Factoring -2 we get

`y=-2[(x-4)^2-1]`

`y=-2(x-4-1)(x-4+1)`

`y=-2(x-5)(x-3)`

is the intercept form