Question

F(x) = x + 7 and g(x) = x - 2, I honestly have no clue where to start im confused

Answer 1

Steps:

So for this question, it asks us for the domain of f(x) ÷ g(x). Set up our function as such:

`((f)/(g))(x)=(x+7)/(x-2)`

Next, we want to find the discontinuity of this function, or the value(s) in which the function cannot equal to. In this case, we need to find the x value that makes the denominator equal to 0 (as anything divided by 0 is undefined). To find it, set the denominator to 0 and solve as such:

`x-2\\eq 0\\x\\eq 2`

Answer:

With the information that we have, the answer is
`\x\`, or the first option.

Answer 2

Answer: A) x

Explanation:

Domain is: all the values that x can be. Look for the following restrictions:

• denominator (bottom) cannot be zero (set denomiantor ≠ zero)
• square root cannot be negative (set inside of square root ≥ 0)
• logs must be positive (set log > 0)

`(f(x))/(g(x)) = (x+7)/(x-2)`

denominator is: x - 2 so set it unequal to zero and solve.

x - 2 ≠ 0

+2 +2

x ≠ 2