For which equations below is x = –3 a possible solution? Check all that apply. |x| = 3 |x| = –3 |–x| = 3 |–x| = –3 –|x| = –3 –|x| = 3

Question

asked May 22, 2019 80.2k views

2 Answers

Burak Cakir · Answer 1 · 2019-05-26T21:36:03+0000

Answer:

The correct options are A, C and E.

Explanation

If a absolution equation is defined as

|x|=a

Then the solutions of the equation are x=a and x=-a.

A.

|x|=3

$x=\pm 3$

So,x=-3 is a solution of this equation.

B.

|x|=-3

This equation has no solution because the value of |x| can no

be negative.

C.

|-x|=3

$-x=\pm 3$

$x=\pm 3$

So,x=-3 is a solution of this equation.

D.

|-x|=-3

This equation has no solution because the value of |-x| can no

be negative.

E.

-|x|=-3

Divide both sides by -1.

|x|=3

$x=\pm 3$

So,x=-3 is a solution of this equation.

F.

-|x|=3

Divide both sides by -1.

|x|=-3

This equation has no solution because the value of |x| can not be negative.

Therefore the correct options are A, C and E.