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The half life of iodine-125 is 60 days. What fraction of iodine-125 nuclides would be left after 360 days?

User Maloney
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2 Answers

7 votes

Final answer:

After 360 days, approximately 0.0156 or 1/64 of the original amount of iodine-125 nuclides would be left.

Step-by-step explanation:

To calculate the fraction of iodine-125 nuclides that would be left after 360 days, we need to determine the number of half-lives that have passed during this period. The half-life of iodine-125 is 60 days, so we can calculate the number of half-lives by dividing 360 days by 60 days.

360 days รท 60 days = 6 half-lives.

Since each half-life reduces the amount of iodine-125 by half, after 6 half-lives, the fraction of iodine-125 nuclides remaining is (1/2)^6, which simplifies to 1/64 or approximately 0.0156.

User Patrick Kelleter
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5 votes

Step-by-step explanation:

The half-life is the time taken for a radioactive substance to decay to half of its original composition.

Let us assume that the original amount is x atoms;

Half - life = 60days

Days Composition Half-life number

0 x 0

60 x/2 1

120 x/4 2

180 x/8 3

240 x/16 4

300 x/32 5

360 x/64 6

The fraction that would be left after 360 days will be
(1)/(64)

User Parilogic
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3.6k points