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Prove that opposite sides of a parallelogram are congruent. Be sure to create and name the appropriate geometric figures.

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Theorem : Opposite sides of a parallelogram are congruent or equal.

Let us suppose a parallelogram ABCD.

Given:
AB\parallel CD and
BC\parallel AD (According to the definition of parallelogram)

We have to prove that: AB is congruent to CD and BC is congruent to AD.

Prove: let us take two triangles,
\bigtriangleup ACD and
\bigtriangleup ABC

In these two triangles,
\angle1=\angle2 { By the definition of alternative interior angles}

Similarly,
\angle4=\angle3

And, AC=AC (common segment)

By ASA,
\bigtriangleup ACD \cong \bigtriangleup ABC

thus By the property of congruent triangle, we can say that corresponding sides of
\bigtriangleup ACD and \bigtriangleup ABC are also congruent.

Thus, AB is congruent to CD and BC is congruent to AD.


Prove that opposite sides of a parallelogram are congruent. Be sure to create and-example-1
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