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Write the equation of a secant line? Screenshot of the question is attached

Write the equation of a secant line? Screenshot of the question is attached-example-1
User Ilmiont
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4 votes

Answer:

y = 12x - 13

Explanation:

The two points you want the line through are ...

... (-4, h(-4)) = (-4, -61)

and

... (2, h(2)) = (2, 11)

The 2-point form of the equation of a line is applicable. For (x1, y1) and (x2, y2), the equation is

... y = (y2-y1)/(x2-x1)·(x-x1) +y1

... y = (-61-11)/(-4-2)·(x -2) + 11 . . . . putting in the point values

... y = 12(x -2) + 11 . . . . . . . . . . . . . simplify

... y = 12x -13 . . . . . . . . . . . . . . . . . eliminate parentheses, collect terms

Write the equation of a secant line? Screenshot of the question is attached-example-1
User NadtheVlad
by
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