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The shadow of a 60 foot pole is a 100 feet long. What is the angle of evaluation from the end of the shadow to the top of the pole?

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Answer:

θ = 36.86°

Explanation:

Given that,

The shadow of a 60 foot pole is a 100 feet long.

We need to find the angle of elevation from the end of the shadow to the top of the pole.

Height, h = 60 foot

Hypotenuse, H = 100 feet

Using trigonometry to find it.


\sin\theta=\frac{\text{Height}}{\text{Hypotenuse}}\\\\\sin\theta=(60)/(100)\\\\\theta=\sin^(-1)((60)/(100))\\\\\theta=36.86^(\circ)

So, the angle of elevation is 36.86 degrees.

User Kroonwijk
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