Question

Water has a specific heat of 4.186 J/g°C. How much heat is required to increase 10.0 g of water from 25.0°C to 30.0°C?

A 5.0 J
B 21 J
C 42 J
D 209 J

Answer 1

10 x 4.186 x (30-25)=209 j

Answer 2

Answer: D) 209 Joules

Step-by-step explanation:

Using the equation below:

`Q= m* c* \Delta T`

Q= heat gained

m= mass of the substance = 10.0 g

`\Delta T` = change in temperature =
`(30-25)^0C=5^0C`

c = heat capacity of water = 4.186 J/g ° C

Putting in all the values we get:

`Q=10g* 4.186J/g^0C* 5^0C`

`Q=209Joules`

Thus heat gained by 10 g of water is 209 Joules