Question

3. y=37x+11y=37x+11 -3x + 7y = 13 Part A: Convert the second equation to slope-intercept form. Show your work! Part B: Determine whether or not the graphs of the lines are parallel. Explain how you know.

Answer 1

We are given first equation y=
`(3)/(7)`x+11.

Second equation is -3x + 7y = 13.

Part A: We need to convert that second equation in slope-intercept form y=mx+b.

In order to convert it in slope-intercept form, we need to isolate it for y.

-3x + 7y = 13

Adding 3x on both sides, we get

-3x+3x + 7y = 3x+13

7y = 3x +13.

Dividing both sides by 7, we get

7y/7 = 3x/7 +13/7.

y= 3/7 x + 13/7.

Slope for first equation y=3/7 x +11 is 3/7 and slope of second equation y= 3/7 x + 13/7 is also 3/7.

Slopes are same for both equations.

Part B: Therefore, lines are parallel due to equal slopes.