Question

The shadow of a 60 foot pole is a 100 feet long. What is the angle of evaluation from the end of the shadow to the top of the pole?

Answer 1

The angle is approximately
`31^(o)`.

Explanation:

The description i the given question can be represented with the sides of a right angled triangle.

Applying the appropriate trigonometric function, we have;

Tan θ =
`(opposite)/(adjacent)`

In the question, opposite side = 60 feet, and adjacent side = 100 feet.

Tan θ =
`(60)/(100)`

= 0.6

θ =
`Tan^(-1)` 0.6

=
`30.964^(o)`

θ =
`31^(o)`

The angle of elevation from the end of the shadow to the top of the pole is
`31^(o)`.