Question

child slide down a hill with an acceleration of 2.9 m/s^2 if she start with an initial velocity of 2.3 how far does she travel in 5.0 second

Answer 1

Distance traveled in 5 seconds = 47.75 meter.

Step-by-step explanation:

We have equation of motion ,
`s= ut+(1)/(2) at^2`, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

In this the velocity of body = 2.3 m/s, acceleration = 2.9
`m/s^2`, we need to calculate displacement when t = 5 seconds.

`s= 2.3*5+(1)/(2) *2.9*5^2=47.75m`

So, distance traveled in 5 seconds = 47.75 meter.