Question

A bicyclist starts from rest and accelerates along a straight path to a speed of 12. 15 m/s in a time of 4. 5 seconds. What is the bicyclist’s acceleration to the nearest tenth of a m/s2?.

Answer 1

Answer:The cyclist's acceleration to the nearest tenth is: C. 2.7 .

Given the following data:

Initial velocity = 0 m/s (since the cyclist starts from rest).

Final velocity = 12.5 m/s.

Time = 4.5 seconds.

To find the cyclist's acceleration to the nearest tenth:

Acceleration is calculated by subtracting the initial velocity from the final velocity and dividing by the time.

Mathematically, acceleration is given by the formula;

Where:

A is the acceleration.

V is the final velocity.

U is the initial velocity.

t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

Acceleration, A = 2.7

Therefore, the cyclist's acceleration to the nearest tenth is 2.7 .

Step-by-step explanation: