Question

C = 7a^4+ + 5a²b2 – 3b^4
D=5a^4 + 7a²b^2 + 3b^4
C - D =

Answer 1

2a^4 +12a

`2 {a}^(4) + 12 { a}^(2) \\ * *`

Answer 2

C-D is:
`\mathbf{4b^4 -2a^b^2 -6b^4}`

Explanation:

We are given:

`C = 7a^4+ + 5a^2b2 - 3b^4\\D=5a^4 + 7a^2b^2 + 3b^4`

We need to find C-D.

Finding C-D we actually have to subtract D from C

So, finding C-D

`C-D\\= 7a^4+ + 5a^2b2 - 3b^4-(5a^4 + 7a^2b^2 + 3b^4)\\=7a^4+ + 5a^2b2 - 3b^4-5a^4-7a^2b^2-3b^4`

Now, combining the like terms.

Like terms are those that have same variables and exponents.

In our case,
`7a^4\: and\: 3b^4, 5a^2b^2\: and\: -7a^b^2, -3b^4\:and\:-3b^4`

`=7a^4 - 3b^4+5a^2b^2 -7a^b^2 -3b^4-3b^4\\=4b^4 -2a^b^2 -6b^4`

So, we get C-D is:
`\mathbf{4b^4 -2a^b^2 -6b^4}`