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Using the equation-x^2-8x-15 what are the coordinates of the vertex

User Rosstex
by
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1 Answer

4 votes

Answer:

(-4, 1)

Explanation:

Start with -x^2-8x-15. Rewrite it as y = -1(x^2 + 8x + 15).

Focus on the terms x^2 + 8x; complete the square here:

x^2 + 8x + 16 - 16, or (x + 4)^2 - 16.

Put this back into y = -1(x^2 + 8x + 15) as follows:

y = -( (x + 4)^2 - 16 + 15)

Simplify this result: y = -(x + 4)^2 + 1

Compare this result to y = a(x-h)^2 + k. See that h = -4 and k = 1.

The coordinates of the vertex are (-4, 1).

User Thepaoloboi
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5.8k points