Question

Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14 times c^2-c-2/c^2-2c-15

Answer 1

Answer: c ≠ {-7, -3, 2, 5}

Explanation:

`(c^(2) - 3c - 10)/(c^(2) + 5c - 14) * (c^(2) - c - 2)/(c^(2) - 2c - 15)`

=
`((c - 5)(c + 2))/((c + 7)(c - 2)) * ((c - 2)(c + 1))/((c - 5)(c +3))`

restrictions:

c + 7 ≠ 0 c - 2 ≠ 0 c - 5 ≠ 0 c + 3 ≠ 0

c ≠ -7 c ≠ 2 c ≠ 5 c ≠ -3