30.4k views
2 votes
K12 help??? 3.12 Congruence and Rigid Motions

K12 help??? 3.12 Congruence and Rigid Motions-example-1
User Kamoy
by
7.2k points

2 Answers

2 votes
congruent because you can map the triangles using a reflection across the y-axis which is a rigid motion
User Basit ZIa
by
7.9k points
5 votes

Answer: ΔPQR is congruent to ΔP'Q'R' because We can map ΔPQR to ΔP'Q'R' using reflection across y-axis. which is a rigid motion.

Explanation:

Given : The coordinates of ΔPQR are P(1,4) , Q(2,2) and R(-2, 1).

The coordinates of ΔP'Q'R' are P(-1,4) , Q(-2,2) and R(2, 1).

Note that the sign of x-coordinate is changed but the magnitude of x and y coordinates remains unchanged.

It means we can ΔP'Q'R' is a mirror image of ΔPQR across y-axis (∵ y-values are exactly same.)

i.e. We can map ΔPQR to ΔP'Q'R' using reflection across y-axis.

Since reflection is a rigid motion and all rigid motions produces congruent images.

⇒ ΔPQR is congruent to ΔP'Q'R'

User Davidjhinson
by
7.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories