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A firecracker is thrown downward from a height of 2.75m above the ground, with a speed of 3.15m/s. Ignore air resistance, determine the height above the ground that the firecracker would be moving at 5.23m/s.

User Jardo
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1 Answer

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Here in this question as we can see there is no air friction so we can use the principle of energy conservation


PE_i + KE_i = PE_f + KE_f


mgh_1 + (1)/(2)mv_i^2 = mgh_2 + (1)/(2)mv_f^2

now here we know that


h_1 = 2.75 m


v_i = 0


v_f = 5.23 m/s

now plug in all values in above equation


mg*2.75 + 0 = mgh + (1)/(2)m(5.23)^2

divide whole equation by mass "m"


9.8*2.75 = 9.8*h + (1)/(2)*27.35


9.8*h = 13.27


h = 1.35 m

so height of the ball from ground will be 1.35 m

User Gonan
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