Answer:
+283.0 kJ·mol⁻¹
Step-by-step explanation:
If reaction 1 reversed is
CO₂ ⟶ CO + ½O₂,
then reaction 1 is
CO + ½O₂ ⟶ CO₂
Reaction 1 is the combustion of carbon monoxide, for which
ΔH = -283.0 kJ·mol⁻¹.
∴ The enthalpy change for reaction 1 reversed is +283.0 kJ·mol⁻¹.