Question

un rectángulo tiene 36 cm de perímetro y 80m2 (a la 2) de área .¿cuales son las dimensiones del rectángulo

Answer 1

Let's assume

length of rectangle is L

width of rectangle is W

we can find perimeter

perimeter =2L+2W

now, we are given

perimeter =36

so, we get

`2L+2W=36`

now, we can solve for L

`L+W=18`

`L=18-W`

now, we can find area

`A=L* W`

we are given area =80

so, we get equation as

`L* W=80`

now, we can plug back L

`(18-W)* W=80`

now, we can solve for W

`18W-W^2=80`

`W^2-18W+80=0`

`(W-8)(W-10)=0`

`W=8,W=10`

now, we can find length

At W=8:

`L=18-8`

`L=10`

At W=10:

`L=18-10`

`L=8`

So, dimensions of rectangle are

Length of rectangle is 10cm

Width of rectangle is 8cm

OR

Length of rectangle is 8cm

Width of rectangle is 10cm ..............Answer