Question

A ball rolls up a hill, going from a speed of 8.09 m/s to a speed of 5.87 m/s in 9.17 seconds. What is its acceleration?

Answer 1

Step-by-step explanation:

Comment

It's actually a deceleration. You should get a negative answer because the ball is slowing down.

Givens

vi = 8.09 m/s

vf = 5.87 m/s

t = 9.17

Formula

a = (vf - vi) /t Substitute the givens into the formula

Solution

a = (5.87 - 8.09)/9.17

Answer

a = - 2.22 m/s^2