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Suppose a parabola has an axis of symmetry at x = -5, a maximum height of 9, and passes through the point (-7,1). write an equation of the parabola in vertex from.

Y = -4(x-5)^2+9
Y = -7(x+9)^2 - 5
Y = -0.06(x-5)^2 + 9
Y = -2(x+5)^2 + 9

Help please...

User Jaybuff
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1 Answer

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We are given

a parabola has an axis of symmetry at x = -5, a maximum height of 9

so, we get

vertex =(-5,9)

vertex=(h,k)=(-5,9)

so, h=-5 and k=9

we can use vertex form of parabola


y=a(x-h)^2+k

we can plug these value


y=a(x+5)^2+9

now, it passes through the point (-7,1)

we can use it and then we can solve for a


1=a(-7+5)^2+9


4a+9=1


4a=-8


a=-2

So, we will get equation of parabola as


y=-2(x+5)^2+9..............Answer


User Caryann
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