Question

Plz help me find answer. what are the coordinates of slope when y= x/1–x² when dy/dx=1​

Answer 1

Explanation:

dy/dx

= d/dx [x / (1 - x²)]

= [(1 - x²)(1) - (x)(-2x)] / (1 - x²)²

= (1 + x²) / (1 - x²)².

When dy/dx = 1, (1 + x²) / (1 - x²)² = 1.

=> 1 + x² = 1 - x²

=> 2x² = 0, x = 0.

Also when x = 0, y = (0) / [1 - (0)²] = 0.

Hence the coodinates is (0, 0).