Question

In the 2002 - 2003 NBA regular season, the Sacramento Kings

won 13 more than twice as many games as they lost, The Kings
played 82 games. How many wins and losses did the team
mave?

Answer 1

Answer: Number of games lost = 23 and Number of games won = 59.

Explanation:

Let x = Number of games lost, y = Number of games won.

y = 13 + 2x (i)

x+ y = 82 (ii)

Substitute value of y from (i) in (ii) , we get

x+ 13 + 2x = 82

⇒ 3x= 82-13

⇒ 3x = 69

⇒ x= 23 [Divide both sides by 3]

Put value of x in (i), y= 13+2(23) = 13+46=59

Hence, Number of games lost = 23 and Number of games won = 59.