Question

Simplify 3 square root of 5 end root minus 2 square root of 7 end root plus the square root of 45 end root minus square root of 28.

Answer 1

`3\sqrt5-2\sqrt7+√(45)-√(28)\\\\=3\sqrt5-2\sqrt7+√(9\cdot5)-√(4\cdot7)\\\\=3\sqrt5-2\sqrt7+\sqrt9\cdot\sqrt5-\sqrt4\cdot\sqrt7\\\\=3\sqrt5-2\sqrt7+3\sqrt5-2\sqrt7\\\\=(3\sqrt5+3\sqrt5)+(-2\sqrt7-2\sqrt7)\\\\=\boxed{6\sqrt5-4\sqrt7}`