Question

Jill and Scott both road their bikes for 30 minutes. Jill traveled 5 kilometers and Scott traveled 10. Calculate each person's speed and tell who rode faster. (s=d/t)

A)Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.

B)Scott had the faster speed since he rode at 10 km/h and Jill was riding at 5 km/h

C)Jill was traveling faster. She was riding at a speed of 10 km/h while Scott was traveling at 20 km/h.

D)Both Jill and Scott were traveling at the same speed since they both rode their bikes for 30 minutes.

Answer 1

Speed of Jill is greater than Scott

Step-by-step explanation:

As we know that

Speed = Distance / Time

So speed of Jill is = 5 / 0.5 since 30 minutes = 0.5 hours

Speed of Jill = 10 km/hour

And

speed of Scott is = 10 / 0.5

Speed of Scott = 20 km/min

Here we can see that speed of Scott is greater than Jill

Answer 2

time for which Jill and Scott both traveled is 30 min

as we know that

1 hour = 60 min

now we will convert the time of travel from minutes to hour

`t = (30 min)/(60 min)* 1 hour`

`t  = 0.5 hour`

now we will have to find the speed of both

For speed we know the formula

`speed = (distance)/(time)`

speed of Jill as he cover 5 km in 30 min

`v_1 = (5)/(0.5) = 10 km/h`

speed of Scott as he cover 10 km in 30 min

`v_2 = (10)/(0.5)= 20 km/h`

so correct answer is

A)Scott had the faster speed since he rode at 20 k/h while Jill only traveled 10 km/h.