Question

retta has 40 raffle tickets to sell. She is required to sell at least 15 tickets. She sells the raffle tickets for $10 each. The amount of money Gretta makes from selling x raffle tickets is represented by a function. f(x)=10x What is the practical range of the function?

Answer 1

it should be 400 considering raffle=x×10=400

Answer 2

[150,400]

Explanation:

Retta has 40 raffle tickets to sell and she has to sell at least 15 tickets. So, the interval that represents this situation is
`[15,40]`, because the minimum allowed is 15 tickets, and the maximum possible is 40 tickets.

We know by given that the function that models this situation is

`f(x)=10x`

To find the valid range, we just need to find the values assigned to
`x=15` and
`x=40`.

`f(x)=10x\\f(15)=10(15)=150`

`f(x)10x\\f(40)=10(40)=400`

Therefore, the practical range of the function is [150,400]