Answer:
44 words
Explanation:
Step one:
given data
The dimension is
7cm long and = 0.07mm
5mm in diameter
radius= 2.5mm
The volume = πr^2h
Volume= 3.142*2.5^2*0.07
Volume= 3.142*6.25*0.07
volume= 1.4 mm^3
If 1.4 mm^3 will write 310 words on an average
1/5(0.2mm^3) liter will write x
cross multiply we have
x= 0.2*310/1.4
x=62/1.4
x=44 words