Question

one of the sides of a square has vertices at (8,-2) and (8,4). What is the length of the side of the square

Answer 1

`length = \sqrt{{(x1 - x2)}^(2) + {(y1 - y2)}^(2) } \\ = \sqrt{ {(8 - 8)}^(2) + {( - 2 - 4)}^(2) } \\ = \sqrt{ {( - 6)}^(2) } \\ = √(36) \\ = 6 \\ therefore \: length \: of \: a \: side \: of \: the \: square \: is \: 6 \: units`