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The path of a softball thrown by maddie forms a parabola wirh the equation y=-3/2401(x-49)^2+8.5 how far does the ball travel vefore it again reaches the same height from which it was thrown

User Etoxin
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Answer:

The distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

Explanation:

The given parabolic equation is


y=-(3)/(2401)(x-49)^2+8.5

Where, h is height of ball after covering x distance horizontally.

Put x=0, to find initial height of the ball.


y=-(3)/(2401)(0-49)^2+8.5


y=-3+8.5


y=5.5

Put y=5.5 in the given equation and find the values of x at which the height of ball is 5.5.


5.5=-(3)/(2401)(x-49)^2+8.5


(3)/(2401)(x-49)^2=-5.5+8.5


(3)/(2401)(x-49)^2=3


(x-49)^2=2401

Take square root both sides.


x-49=\pm 49


x=\pm 49+49


x=0,98

The height of ball is 5.5 at x=0 and x=98.

Therefore distance travelled by ball is 98 units before it again reaches the same height from which it was thrown.

The path of a softball thrown by maddie forms a parabola wirh the equation y=-3/2401(x-example-1
User John Halbert
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