Answer:
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Explanation:
The equation of a circle can be represented as;
(x-h)^2 + (y-k)^2 = r^2
r is the radius while (h,k) represents the coordinates of the center
Thus, we have that;
(x-2)^2 + (y+3)^2
That would give;
x^2 - 4x + 4 + y^2 + 6y + 9
The sum of values with no coefficient is;
4 + 9 = 13
If we take this to the other side, we can have 13 + 3 = 16
The square root of this is then 4
Mathematically, we can therefore express the equation of the circle as;
(x-2)^2 + (y-+3)^2 = 4^2
By expansion, we will get the original given equation