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Find the vertex of the function h(x) = -x^2 + 14
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3 votes
Find the vertex of the function
h(x) = -x^2 + 14

User Ben Burns
by
7.3k points

1 Answer

5 votes

The vertex form:


f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex



h(x)=-x^2+14=-(x-0)^2+14\to h=0,\ k=14

Answer: (0, 14).

User Mei
by
8.2k points
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