Question

Find the vertex of the function
h(x) = -x^2 + 14

Answer 1

The vertex form:

`f(x)=a(x-h)^2+k\\\\(h,\ k)-vertex`

`h(x)=-x^2+14=-(x-0)^2+14\to h=0,\ k=14`

Answer: (0, 14).