Question

Level:8th

Rewrite one eighth times x cubed times y plus seven eighths times x times y squared using a common factor.

one fourth times x times y times the quantity 4 times x squared plus 28 times y end quantity

one fourth times x times y times the quantity x squared plus 7 times y end quantity

one eighth times x cubed times y squared times the quantity y plus 7 times x end quantity

one eighth times x times y times the quantity x squared plus 7 times y end quantity

Answer 1

Answer: The dude above is right ;)

Explanation:

#Stranger Things

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Answer 2

First statement;

`{ \tt{ (1)/(8) {x}^(3)y + (7)/(8) x {y}^(2) }} \\ \\ = { \boxed{ \tt{ (1)/(8)xy( {x}^(2) + 7y)}}}`

Second statement;

`{ \tt{ ((1)/(4)y 4{x}^(3) ) + 28y}} \\ \\`

Third statement;

`{ \tt{( (1)/(4) y {x}^(3)) + 7y }} \\ \\`

Forth statement;

`{ \tt{ (1)/(8)x {}^(3) {y}^(3) + 7x }} \\ \\`

Fifth statement;

`{ \tt{ (1)/(8)x {}^(2) y + 7y }}`