Question

How many grams of H2O2 will be produced if 14.86-grams of water is reacted with excess oxygen? How many molecules of H2O2 were produced?

2H2O (l) + O2 (g) ® 2H2O2 (aq)

Answer 1

4.99 ×10²³ molecules

Mass = 28.22 g

Step-by-step explanation:

Given data:

Mass of H₂O₂ produced = ?

Mass of water react = 14.86 g

Number of molecules of H₂O₂ produced = ?

Solution:

Chemical equation:

2H₂O + O₂ → 2H₂O₂

Number of moles of water:

Number of moles = mass/molar mass

Number of moles = 14.86 g/ 18 g/mol

Number of moles = 0.83 mol

Now we will compare the moles of water and H₂O₂.

H₂O : H₂O₂

2 : 2

0.83 : 0.83

Mass of H₂O₂:

Mass = number of moles × molar mass

Mass = 0.83 mol × 34 g/mol

Mass = 28.22 g

Number of molecules:

1 mole = 6.022×10²³ molecules

0.83 mol × 6.022×10²³ molecules / 1 mol

4.99 ×10²³ molecules