Question

A particle moving at a velocity of 4.7 m/s

in the positive r direction is given an accel-
eration of 5.4 m/s in the positive y direction
for 0.1 s.
What is the final speed of the particle?

Answer 1

5.24m/s

Step-by-step explanation:

Given parameters:

Initial velocity = 4.7m/s

Acceleration = 5.4m/s²

Time = 0.1s

Unknown:

Final velocity of the particle = ?

Solution:

Acceleration is the rate of change of velocity with time.

Acceleration =
`(v - u)/(t)`

v is the final velocity

u is the initial velocity

t is the time taken

Now find v;

5.4 =
`(v - 4.7)/(0.1)`

0.54 = v - 4.7

v = 5.24m/s