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What is the equation of a parabola with a vertex at the origin and the graph containing (-3,3)?

1 Answer

2 votes

Answer:


y=\frac13x^2

Explanation:

Each parabola
y=ax^2 has a vertex at the origin.

Point (-3,3) means that x=-3, y=3 substitute it to the equation
y=ax^2 and calculate "a".


3=a\cdot (-3)^2\\ 3=a\cdot 9\\ 3=9a\\ 9a=3\ \ \ \ |:9\\ a=\frac39\\ a=\frac13

Put
a=\frac13 to the equation
y=ax^2


y=\frac13x^2

User Joakim Johansson
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