Question

The number of carbon atoms in 9.30x10^-3 moles of Na2CO3​

Answer 1

Answer:
`56* 10^(20)\ \text{atoms}`

Step-by-step explanation:

Given

No. of moles of
`Na_(2)CO_(3)` is
`9.30* 10^(-3)`

So, for
`9.30* 10^(-3)` moles of
`Na_(2)CO_(3)`

There are
`9.30* 10^(-3)* 6.022* 10^(23)\ \text{molecules of}\ Na_(2)CO_(3)=56* 10^(20)\ \text{molecules}`

1 molecule of
`Na_(2)CO_(3)` contains 1 atom of carbon

i.e. there are
`56* 10^(20)\ \text{atoms of C}`