Answer:
C. Steve is 5⁄6 as fast as Paul
Explanation:
For, Steve,
Distance = 100 m,
Time = 10 seconds,
Now, For Paul,
Distance = 100 m,
Time = 12 seconds,
Since, the distance for both are same,
Thus,
![\frac{\text{Steve's time}}{\text{Paul's time}}=(10)/(12)](https://img.qammunity.org/2019/formulas/mathematics/high-school/k6d85y18n34t99vcxuhp4n0k9qlm9t6tbr.png)
![=(5)/(6)](https://img.qammunity.org/2019/formulas/mathematics/high-school/wyx2xqibcrieziz9rfaytq4pvsh25i90eu.png)
![\implies \text{Steve's time}=(5)/(6)\text{ of Paul's time}}](https://img.qammunity.org/2019/formulas/mathematics/high-school/vid5tyh706okqggmp439z0ztpbtjozc758.png)
Hence, Steve's time is 5⁄6 of the time taken by Paul.
Option C is correct.