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What is the equation of a parabola in vertex form for a line that passed through (5,-4) and has vertex (-2,5)

User Malisokan
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\text{The vertex form of a parabola}\\\\y=a(x-h)^2+k\\\\\text{We have the vertex}\ (-2,\ 5)\to h=-2,\ k=5.\\\\\text{Substitute}\\\\y=a(x-(-2))^2+5=a(x+2)^2+5\\\\\text{We have the point}\ (5,\ -4).\\\text{Substitute the coordinates of the point to the equation:}\\\\-4=a(5+2)^2+5\\\\-4=a(7)^2+5\\\\-4=49a+5\qquad|-5\\\\-9=49a\qquad|:49\\\\a=-(9)/(49)\\\\Answer:\ \boxed{y=-(9)/(49)(x+2)^2+5}

User Lord Zsolt
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