Question 1

I just need to see how to work this problem out, so I don't have to ask a question like this again..and I know what I'm doing next time! Thanks :)

20 pts!

−6x+12>24=

Question 2

Answer by Mimiwhatsup:

$-6x+12>24\\\mathrm{Subtract\:}12\mathrm{\:from\:both\:sides}\\-6x+12-12>24-12\\Simplify\\-6x>12\\Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)\\\left(-6x\right)\left(-1\right)<12\left(-1\right)\\Simplify\\6x<-12\\\mathrm{Divide\:both\:sides\:by\:}6\\(6x)/(6)<(-12)/(6)\\Simplify\\(6x)/(6)\\(6x)/(6)\\\mathrm{Divide\:the\:numbers:}\:(6)/(6)=1\\=x\\(-12)/(6)=-2\\(-12)/(6)\\\mathrm{Apply\:the\:fraction\:rule}:\quad (-a)/(b)=-(a)/(b)\\$

$=-(12)/(6)\\\mathrm{Divide\:the\:numbers:}\:(12)/(6)=2\\=-2\\Answer is: x<-2$

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