Question

Graph the line for y-1=7(x - 2) on the coordinate plane

Answer 1

The point-slope form:

`y=y_1=m(x-x_1)\\\\(x_1,\ y_1)-point\\m-slope`

We have

`y-1=7(x-2)`

Therefore

the point = (2, 1)

the slope = 7

The slope
`m=(\Delta y)/(\Delta x)=7\to(\Delta y)/(\Delta x)=(7)/(1)`

7 units up and 1 unit right.

-------------------------------------------------------------------------------

Other method.

`y-1=7(x-2)\qquad|\text{use distributive property}\\\\y-1=7x-14\qquad|+1\\\\y=7x-13`

It's the slope-intercept form.

for x = 0 → y = 7(0) - 13 = 0 - 13 = -13 → (0, 13)

for x = 2 → y = 7(2) - 13 = 14 - 13 = 1 → (2, 1)