Answer:
The ΔABD and ΔCDB are congruent by SAS concurrency.
Explanation:
First please take a look with diagram in attachment.
In ΔABD and ΔCDB
AB=CD { Given in question}
BD=DB {Common in both triangle}
Therefor, ΔABD and ΔCDB are congruent by SAS
by CPCT
AD=CB by CPCT
But
and
are pair of alternate interior angle.
Therefore, AD parallel to CB (AD||CB) and AD=CB
We are given AB parallel to CD (AB||CD) and AB=CD
It means quadrilateral ABCD would be parallelogram because opposite sides are equal and parallel.