Explanation:
First , Split the given shape into two parts : Trapezium and rectangle :
Here , 18 m and 11 m are the opposite parallel side and (15-8) = 7m is the height of the trapezium.
![\boxed{ \sf{Area \: of \: trapezium = (1)/(2) h(a + b)}}](https://img.qammunity.org/2022/formulas/mathematics/college/ta91lkx582alefjxbpbqesaepj0lumz2i3.png)
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![\tt{ (1)/(2) * 7(18 + 11})](https://img.qammunity.org/2022/formulas/mathematics/college/zw3fuvqhifq7fuwruev9oeu4x4lmis548a.png)
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![\sf{ (1)/(2) * 7 * 29}](https://img.qammunity.org/2022/formulas/mathematics/college/w2hzbc12x6x46xy8crcbcvqhad1ehv9vgb.png)
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![\sf{101.5 \: {m}}^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/9zbx2ykggzc42gzjz4uamn3yydv9x287np.png)
Area of trapezium = 101.5 m²
In rectangle , 18 m is the length and 8 m is the width.
![\boxed{ \sf{Area \: of \: a \: rectangle = l * w}}](https://img.qammunity.org/2022/formulas/mathematics/college/30mvuqyo0fs17rf5uiajrzb428eovk9hv6.png)
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![\sf{18 \: m \: * 8 \: m}](https://img.qammunity.org/2022/formulas/mathematics/college/nkq4y95d9ggli4whacxmnr733gefpyy6v2.png)
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![\sf{144 \: {m}}^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/w7lmlmqwm085hw1auh6lwgqkvqt8iltdp7.png)
Area of a rectangle = 144 m
Now , Finding total area of given shape :
![\boxed{ \sf{Total \: area = Area \: of \: trapezium + area \: of \: a \: rectangle}}](https://img.qammunity.org/2022/formulas/mathematics/college/jor5z8nzjqy8ntgtjmb7gymhboomus8r47.png)
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![\sf{101.5 \: {m}^(2) + 144 \: {m}}^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/85zuo2ltrn0if95qzdq56o68k26o554o15.png)
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![\sf{245.5 {m}}^(2)](https://img.qammunity.org/2022/formulas/mathematics/college/4v4oln69o14zstwea00c029irkzyzskv13.png)
![\red{ \boxed{ \boxed{ \tt{⇾ \: Our \: final \: answer : \boxed{ \underline{ \tt{245.5 \: {m}^(2) }}}}}}}](https://img.qammunity.org/2022/formulas/mathematics/college/h6rxgqn8lr2jhw86siqtnfk4yjquudptms.png)
Hope I helped ! ツ
Have a wonderful day / night ! ♡
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