Question

Whats the answer for 6b+7-2b=1+5b

Answer 1

b=6

Explanation:

We have the expression
`6b+7-2b=1+5b`

We are to leave in one side of the expression all the terms that has b and in the other the terms that doesn't have b.

`6b+7-2b=1+5b\\6b-2b-5b=1-7`

We can apply common factor b in the left side, and resolve the subtraction in the right side.

`b(6-2-5)=-6\\b(-1)=-6`

Now divide both sides in (-1).

`b(-1)=-6\\(b(-1))/((-1))=((-6))/((-1)) \\b=6`

Then the answer of
`6b+7-2b=1+5b` is b=6.

Answer 2

`Solution,6b+7-2b=1+5b\quad :\quad b=6`

`Steps:`

`6b+7-2b=1+5b`

`\mathrm{Group\:like\:terms}, 6b-2b+7=1+5b`

`\mathrm{Add\:similar\:elements:}\:6b-2b=4b, 4b+7=1+5b`

`\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}, 4b+7-7=1+5b-7`

`\mathrm{Simplify}, 4b=5b-6`

`\mathrm{Subtract\:}5b\mathrm{\:from\:both\:sides}, 4b-5b=5b-6-5b`

`\mathrm{Simplify}, -b=-6`

`\mathrm{Divide\:both\:sides\:by\:}-1, (-b)/(-1)=(-6)/(-1)`

`\mathrm{Simplify}, b=6`

`\mathrm{The\:Correct\:Answer\:is\:b=6}`

`\mathrm{Hope\:This\:Helps!!!}`

`\mathrm{-Austint1414}`