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Find the factorization of the polynomial below. 100x^2-20x+1

A. (10x+1)^2
B. (10-1)^2
C. (50x+1)^2
D. (50x-1)^2

User Royan
by
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2 Answers

4 votes

Answer:B

Explanation:

User Jeyhun Rahimov
by
5.6k points
5 votes

ANSWER

The factorization of
100x^2-20x+1

is
(10x-1)^2.


EXPLANATION

We want to factor
100x^2-20x+1


Comparing this to
ax^2+bx+c



a=100,b=-20,c=1



ac=100

We look for factors of 100 that add up to
-20.


These factors are
-10,-10


We now split the middle term to obtain;



100x^2-10x-10x+1

We factor to obtain;


10x(10x-1)-1(10x-1)


This simplifies to
(10x-1)(10x-1)=(10x-1)^2


User BrainCrash
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5.4k points